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[遊戲連結] 5 Dragons (Aristocrat)
ReelSize: 3x5
Paylines: 243 Way
Provider: Aristocrat
Features: ExtraBet, RandomMultiplier, WildMultiplier
Except for the extra bet, the base game has no other features, so the following spreadsheet will not explain more.
Next, multiply the wild-passed connection payments by the average multiplier of the wild. The average multiplier is adjusted on the page of free spins. Paste the average multiplier to use, and then explain how to adjust the average multiplier .
The bottom of the connection combination is another feature of the game. When the first and fifth reels appear H5, you can get additional random multiples. Similar to the scatter symbol calculation, but the payment becomes random.
Here is only one free game as an example, the other 4 options are also the same calculation.
Here is the calculation of free spins. The weights of the two random multipliers are also adjusted here. The advantage of putting them together is better to compare. Because this kind of multi-option game, the average payment of each option must be the same, so that the overall RTP of the game will be the same.
Note: The reel strips used in the par sheet may not be the real strips of the game.
Parsheet_08 - 5Dragons (Aristocrat)
ReelSize: 3x5
Paylines: 243 Way
Provider: Aristocrat
Features: ExtraBet, RandomMultiplier, WildMultiplier
Game Instructions
The model is the same as Parsheet_05. The difference is that the payline is 243 way, and the multiplier is random.Model Descriptions
Base Game
In base game, you can bet an extra 5 points, allowing 5 more rounds of free games. In terms of the model, the mini bet changes with the number of free games. Therefore, we only teach the version with additional bets.Except for the extra bet, the base game has no other features, so the following spreadsheet will not explain more.
Free Game
In free game, because the payment will be different when connection passed to the wild, it is necessary to split the symbol connection into the part that has passed the wild and the part that has not passed the wild. The CH1 here is the number of connections that H1 can contribute on the reel.Next, multiply the wild-passed connection payments by the average multiplier of the wild. The average multiplier is adjusted on the page of free spins. Paste the average multiplier to use, and then explain how to adjust the average multiplier .
The bottom of the connection combination is another feature of the game. When the first and fifth reels appear H5, you can get additional random multiples. Similar to the scatter symbol calculation, but the payment becomes random.
Here is only one free game as an example, the other 4 options are also the same calculation.
Here is the calculation of free spins. The weights of the two random multipliers are also adjusted here. The advantage of putting them together is better to compare. Because this kind of multi-option game, the average payment of each option must be the same, so that the overall RTP of the game will be the same.
Simulation Result
File Download
Here is the par sheet of this game, if you are interested, you can download the par sheet file for research.Note: The reel strips used in the par sheet may not be the real strips of the game.
Parsheet_08 - 5Dragons (Aristocrat)
[遊戲連結] 5 Dragons (Aristocrat)
滾輪大小: 3x5
連線方式: 243 Way
遊戲開發商: Aristocrat
遊戲特色: 額外押注、隨機倍數、多選項遊戲
這款主遊戲裡面可以額外押注5分,讓免費遊戲可以再多5局。以模型上來說,就是基本押注跟免費遊戲局數改變而已,因此這邊只針對額外押注的版本去做教學,沒有額外押注的部分讀者可以嘗試自行擴充。
除了額外押注之外,主遊戲沒有其他特色,因此下方試算表就不多做說明。
接著將有經過百搭的連線配分乘上百搭的平均倍數,平均倍數筆者是放在免費遊戲場次那頁統一調整,這邊就先將平均倍數拉過來使用,後面再說明怎麼調整平均倍數。
連線組合的最下面,是遊戲的另一個特色,第一與第五滾輪出現H5時可以得到額外的隨機倍數。類似分散圖標算法,只是分數變成是隨機的。
這邊只放一個免費遊戲為例,另外4個選項也是同樣算法。
這下面就是免費遊戲場次的運算。兩個隨機倍數的權重也是在這邊調整,放在一起的好處是比較好比較,因為這種多選項的遊戲,必須要讓每個選項的平均得分都相同,才不會讓玩家因為做了不同選擇,而對遊戲的整體RTP會有差異。
注意:試算表中使用滾輪未必為遊戲真實滾輪。
Parsheet_08 - 5Dragons (Aristocrat)
滾輪大小: 3x5
連線方式: 243 Way
遊戲開發商: Aristocrat
遊戲特色: 額外押注、隨機倍數、多選項遊戲
模型說明
這次要教學的模型,跟模型教學05一樣也是倍數百搭,不同的地方是這次的連線方式是243路,並且倍數是隨機的。這款主遊戲裡面可以額外押注5分,讓免費遊戲可以再多5局。以模型上來說,就是基本押注跟免費遊戲局數改變而已,因此這邊只針對額外押注的版本去做教學,沒有額外押注的部分讀者可以嘗試自行擴充。
除了額外押注之外,主遊戲沒有其他特色,因此下方試算表就不多做說明。
符號解釋
免費遊戲中,因為遇到百搭得分會不同,因此需要圖標連線拆成有經過百搭與沒經過百搭的部分,這邊的CH1就是H1在滾輪上能貢獻的連線數量。接著將有經過百搭的連線配分乘上百搭的平均倍數,平均倍數筆者是放在免費遊戲場次那頁統一調整,這邊就先將平均倍數拉過來使用,後面再說明怎麼調整平均倍數。
連線組合的最下面,是遊戲的另一個特色,第一與第五滾輪出現H5時可以得到額外的隨機倍數。類似分散圖標算法,只是分數變成是隨機的。
這邊只放一個免費遊戲為例,另外4個選項也是同樣算法。
這下面就是免費遊戲場次的運算。兩個隨機倍數的權重也是在這邊調整,放在一起的好處是比較好比較,因為這種多選項的遊戲,必須要讓每個選項的平均得分都相同,才不會讓玩家因為做了不同選擇,而對遊戲的整體RTP會有差異。
模擬結果
檔案下載
以上就是這一款遊戲的模型教學,有興趣的可以自行下載試算表研究注意:試算表中使用滾輪未必為遊戲真實滾輪。
Parsheet_08 - 5Dragons (Aristocrat)
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